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2019 Kobe Challenger – Doubles

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Doubles
2019 Kobe Challenger
Final
ChampionsIndia Purav Raja
India Ramkumar Ramanathan
Runners-upSweden André Göransson
Indonesia Christopher Rungkat
Score7–6(8–6), 6–3
Events
Singles Doubles
← 2018 · Kobe Challenger · 2022 →

Gonçalo Oliveira and Akira Santillan were the defending champions[1] but chose to defend their title with different partners. Oliveira partnered Brydan Klein but withdrew in the first round. Santillan partnered Bradley Mousley but lost in the first round to Nam Ji-sung and Song Min-kyu.

Purav Raja and Ramkumar Ramanathan won the title after defeating André Göransson and Christopher Rungkat 7–6(8–6), 6–3 in the final.

Seeds

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Draw

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Key

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First round Quarterfinals Semifinals Final
1 Australia M Reid
Australia L Saville
0 6 [9]
WC Japan T Ichikawa
Japan S Watanabe
6 5 [4] Japan T Matsui
Japan Yo Watanuki
6 4 [11]
Japan T Matsui
Japan Yo Watanuki
3 7 [10] Japan T Matsui
Japan Yo Watanuki
3 4
4 India P Raja
India R Ramanathan
4 4 India P Raja
India R Ramanathan
6 6
Thailand Sa Ratiwatana
Thailand So Ratiwatana
2r 4 India P Raja
India R Ramanathan
7 2 [10]
South Korea J-s Nam
South Korea M-k Song
6 3 [10] South Korea J-s Nam
South Korea M-k Song
5 6 [7]
Australia B Mousley
Australia A Santillan
4 6 [7] 4 India P Raja
India R Ramanathan
78 6
China Y Bai
China Z Li
77 6 2 Sweden A Göransson
Indonesia C Rungkat
66 3
WC Japan Shintaro Imai
Japan T Niki
61 4 China Y Bai
China Z Li
7 6
WC Japan S Hazawa
Japan Y Shimizu
3 Chinese Taipei C-p Hsieh
Chinese Taipei T-h Yang
5 3
3 Chinese Taipei C-p Hsieh
Chinese Taipei T-h Yang
w/o China Y Bai
China Z Li
2 0
United Kingdom B Klein
Portugal G Oliveira
2 Sweden A Göransson
Indonesia C Rungkat
6 6
India A Kadhe
Spain E López Pérez
w/o India A Kadhe
Spain E López Pérez
4 2
Chinese Taipei C-h Tseng
Chinese Taipei T-l Wu
4 3 2 Sweden A Göransson
Indonesia C Rungkat
6 6
2 Sweden A Göransson
Indonesia C Rungkat
6 6

References

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  1. ^ "Kobe | Overview | ATP Tour | Tennis".
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